Problem

$\left(\frac{\tan A+\sec A-1}{\tan A-\sec A+1}\right)$ is equal to

Answer

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Answer

\boxed{\frac{-\sqrt{2}\cos(A + \frac{\pi}{4}) + 1}{\sqrt{2}\sin(A + \frac{\pi}{4}) - 1}}

Steps

Step 1 :Given expression: \(\frac{\tan A + \sec A - 1}{\tan A - \sec A + 1}\)

Step 2 :Simplified expression: \(\frac{-\sqrt{2}\cos(A + \frac{\pi}{4}) + 1}{\sqrt{2}\sin(A + \frac{\pi}{4}) - 1}\)

Step 3 :\boxed{\frac{-\sqrt{2}\cos(A + \frac{\pi}{4}) + 1}{\sqrt{2}\sin(A + \frac{\pi}{4}) - 1}}

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