If A=left{x ; x^{3}-3 x^{2}+2 x=0right}, B=left{x ; x^{2}-2 x=0right} then A cup B is

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Step:1 ：Solve the equations: (x^3 - 3x^2 + 2x = 0) and (x^2 - 2x = 0) to find the elements of sets A and BStep:2 ：A = {0, 1, 2}, B = {0, 2}Step:3 ：boxed{A cup B = {0, 1, 2}}

Answer

Step: 1 ：Solve the equations: (x^3 - 3x^2 + 2x = 0) and (x^2 - 2x = 0) to find the elements of sets A and BStep: 2 ：A = {0, 1, 2}, B = {0, 2}Step: 3 ：boxed{A cup B = {0, 1, 2}}

If $A=\left\{x ; x^{3}-3 x^{2}+2 x=0\right\}, B=\left\{x ; x^{2}-2 x=0\right\}$ then $A \cup B$ is

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