Find $\frac{d^{2} y}{d x^{2}}$
$y = \sqrt[3]{x}$
$\frac{d^{2} y}{d x^{2}} =$

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Final Answer: The second derivative of the function $y = \sqrt[3]{x}$ is $- \frac{2}{9} x^{- \frac{5}{3}}$ .

Steps

Step 1 ：Find the first derivative of the function $y = \sqrt[3]{x}$ . The derivative is $y^{'} = \frac{1}{3} x^{- \frac{2}{3}}$ .

Step 2 ：Find the second derivative by taking the derivative of the first derivative. The second derivative of the function $y = \sqrt[3]{x}$ is $y^{″} = - \frac{2}{9} x^{- \frac{5}{3}}$ .

Step 3 ：Final Answer: The second derivative of the function $y = \sqrt[3]{x}$ is $- \frac{2}{9} x^{- \frac{5}{3}}$ .

Find d2ydx2y=x3d2ydx2=

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Find $\frac{d^{2} y}{d x^{2}}$
$y = \sqrt[3]{x}$
$\frac{d^{2} y}{d x^{2}} =$