4. Right triangular pyramid
\[
\begin{array}{l}
V=40.15 \mathrm{ft}^{3} \\
\text { leg } 1 \text { of base }=13.2 \mathrm{ft} \\
\text { leg } 2 \text { of base }= \\
h=5 \mathrm{ft}
\end{array}
\]

Answer

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Answer

\(\boxed{\text{Final Answer: The leg 2 of the base of the right triangular pyramid is approximately 3.65 ft.}}\)

Steps

Step 1 ：Given the volume formula for a right triangular pyramid: V = (1/3) * (1/2) * leg1 * leg2 * h

Step 2 ：Plug in the known values: 40.15 = (1/3) * (1/2) * 13.2 * leg2 * 5

Step 3 ：Solve for leg2: leg2 = \(\frac{40.15 * 3 * 2}{13.2 * 5}\)

Step 4 ：Calculate leg2: leg2 ≈ 3.65

Step 5 ：\(\boxed{\text{Final Answer: The leg 2 of the base of the right triangular pyramid is approximately 3.65 ft.}}\)