Problem

Which is $\sin 2 \theta$ when $\cos \theta=-\frac{3}{5}$ and $0< \theta< \pi$ ?

Answer

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Answer

\(\boxed{-\frac{24}{25}}\) is the final answer

Steps

Step 1 :Given: \(\cos\theta = -\frac{3}{5}\) and \(0 < \theta < \pi\)

Step 2 :Use the Pythagorean identity: \(\sin^2\theta + \cos^2\theta = 1\)

Step 3 :Calculate \(\sin^2\theta = 1 - \cos^2\theta = 1 - \left(-\frac{3}{5}\right)^2 = \frac{16}{25}\)

Step 4 :Find \(\sin\theta = \sqrt{\frac{16}{25}} = \frac{4}{5}\) since \(\sin\theta\) is positive

Step 5 :Use the double angle formula: \(\sin 2\theta = 2\sin\theta\cos\theta\)

Step 6 :Calculate \(\sin 2\theta = 2\left(\frac{4}{5}\right)\left(-\frac{3}{5}\right) = -\frac{24}{25}\)

Step 7 :\(\boxed{-\frac{24}{25}}\) is the final answer

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