\[
\begin{array}{l}
x+2 y-3 z=2 \\
x-3 y-z=3 \\
-x+3 y+(4-k) z=7
\end{array}
\]
If we don't apply the Cramer's method to the given linear system then find the value for $k$.

Answer

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Answer

Eliminate y from the new equations to find the value of k: $\boxed{k = \frac{-2x + 16y + z - 2}{z}}$

Steps

Step 1 ：Eliminate x from the first two equations and then from the second and third equations to get two new equations: $5y - 2z = -1$ and $2x - 6y - z(4 - k) - z = -4$

Step 2 ：Eliminate y from the new equations to find the value of k: $\boxed{k = \frac{-2x + 16y + z - 2}{z}}$

\[\begin{array}{l}x+2 y-3 z=2 \\x-3 y-z=3 \\-x+3 y+(4-k) z=7\end{array}\]If we don't apply the Cramer's method to the given linear system then find the value for $k$.

Answer

Popular Problems

\[
\begin{array}{l}
x+2 y-3 z=2 \\
x-3 y-z=3 \\
-x+3 y+(4-k) z=7
\end{array}
\]
If we don't apply the Cramer's method to the given linear system then find the value for $k$.