The cosine of the difference of two angles " $\cos (\alpha-\beta) \quad$ " equals the
Answer
The final answer is: The cosine of the difference of two angles ' \(\cos (\alpha-\beta) \) ' equals the cosine of the first angle times the cosine of the second angle plus the sine of the first angle times the sine of the second angle. This can be represented as \(\boxed{\cos(\alpha)\cos(\beta) + \sin(\alpha)\sin(\beta)}\)
Step 1 ：The cosine of the difference of two angles ' \(\cos (\alpha-\beta) \) ' can be expressed in terms of the cosines and sines of the two angles. The formula is: \(\cos(\alpha - \beta) = \cos(\alpha)\cos(\beta) + \sin(\alpha)\sin(\beta)\)
Step 2 ：The final answer is: The cosine of the difference of two angles ' \(\cos (\alpha-\beta) \) ' equals the cosine of the first angle times the cosine of the second angle plus the sine of the first angle times the sine of the second angle. This can be represented as \(\boxed{\cos(\alpha)\cos(\beta) + \sin(\alpha)\sin(\beta)}\)
