What is the domain of y=3 cdot 2^{sqrt{x}} ?

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Accepted Answer

Step:1 ：The function given is (y=3 cdot 2^{sqrt{x}}).Step:2 ：The base of the exponent, 2, can take any exponent and still be a real number.Step:3 ：However, the exponent is (sqrt{x}), which means x must be greater than or equal to 0, because we cannot take the square root of a negative number in the real number system.Step:4 ：Therefore, the domain of this function is all real numbers greater than or equal to 0.Step:5 ：(boxed{x geq 0})

Answer

Step: 1 ：The function given is (y=3 cdot 2^{sqrt{x}}).Step: 2 ：The base of the exponent, 2, can take any exponent and still be a real number.Step: 3 ：However, the exponent is (sqrt{x}), which means x must be greater than or equal to 0, because we cannot take the square root of a negative number in the real number system.Step: 4 ：Therefore, the domain of this function is all real numbers greater than or equal to 0.Step: 5 ：(boxed{x geq 0})

What is the domain of $y=3 \cdot 2^{\sqrt{x}}$ ?

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