$f(x)=\sqrt{x}+7$. Find the inverse of $f(x)$ and its domain.
\(f^{-1}(x) = (x - 7)^2\) and its domain is \([7, \infty)\)
Step 1 :Swap x and y: \(x = \sqrt{y} + 7\)
Step 2 :Solve for y: \(y = (x - 7)^2\)
Step 3 :\(f^{-1}(x) = (x - 7)^2\) and its domain is \([7, \infty)\)