Which point satisfies the inequality $3 x-2 y \leq 10$ ?
$(7,1) \quad(5,-3)$
$(3,5) \quad(-1,-7)$

Answer

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Answer

\boxed{(3, 5)} is the point that satisfies the inequality $3x - 2y \leq 10$

Steps

Step 1 ：Check which of the given points satisfy the inequality $3x - 2y \leq 10$:

Step 2 ：For point (7, 1): $3(7) - 2(1) = 21 - 2 = 19 $, 19 is not less than or equal to 10.

Step 3 ：For point (5, -3): $3(5) - 2(-3) = 15 + 6 = 21 $, 21 is not less than or equal to 10.

Step 4 ：For point (3, 5): $3(3) - 2(5) = 9 - 10 = -1 $, -1 is less than or equal to 10.

Step 5 ：For point (-1, -7): $3(-1) - 2(-7) = -3 + 14 = 11 $, 11 is not less than or equal to 10.

Step 6 ：\boxed{(3, 5)} is the point that satisfies the inequality $3x - 2y \leq 10$