Solve the equation $5 x^{2}+8 x-23=0$
Show your working clearly.
Give your solutions correct to 3 significant figures.
What is the positive solution?
\(\boxed{x \approx 1.489}\) is the positive solution
Step 1 :Given the quadratic equation: \(5x^2 + 8x - 23 = 0\)
Step 2 :Use the quadratic formula: \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\)
Step 3 :Substitute the values: \(a = 5\), \(b = 8\), and \(c = -23\)
Step 4 :Calculate the discriminant: \(\Delta = b^2 - 4ac = 524\)
Step 5 :Find the two possible solutions for x: \(x_1 = \frac{-8 + \sqrt{524}}{10}\) and \(x_2 = \frac{-8 - \sqrt{524}}{10}\)
Step 6 :Calculate the values of \(x_1\) and \(x_2\): \(x_1 \approx 1.489\) and \(x_2 \approx -3.089\)
Step 7 :\(\boxed{x \approx 1.489}\) is the positive solution