Problem

Solve for a:
$\sqrt{4 + \sqrt{16 + 16 a}} + \sqrt{1 + \sqrt{1 + a}} = 6 .$
${(7 b^{3})}^{2} \cdot {(4 b^{2})}^{- 3}$ , given that bis non-zero.

Answer

Expert–verified

Hide Steps

Answer

Solve for a: $a = 8$

Steps

Step 1 ：Square both sides of the equation: ${(\sqrt{4 + \sqrt{16 + 16 a}} + \sqrt{1 + \sqrt{1 + a}})}^{2} = 6^{2}$

Step 2 ：Solve for a: $a = 8$

link_gpt

Popular Problems

Compute $\int_{0}^{\ln (2) / … Solve the triangle. \[ \mathr… QUESTION 2 - 1 POINT Solve th… 5. Suppose you are a computer… Answer the statistical measur… $(-\infty, 2) \cap(-6, \infty… A firm does not pay a dividen… Math 112 Section: 4. Tubercul… Find

y^{'}

if $y=\ln \… 3. (3pts) Cherry trees in a c… More