You have found the following ages (in years) of all 4 bears at your local zoo:
$5, 4, 6, 39$
What is the average age of the bears at your zoo? What is the standard deviation? Round your answers to the nearest tenth.

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Answer

$Standard Deviation = \sqrt{\frac{(5 - 13.5)^{2} + (4 - 13.5)^{2} + (6 - 13.5)^{2} + (39 - 13.5)^{2}}{4}} \approx 14.6$

Steps

Step 1 ： $Average = \frac{5 + 4 + 6 + 39}{4} = \frac{54}{4}$

Step 2 ： $Deviation : (5 - 13.5)^{2}, (4 - 13.5)^{2}, (6 - 13.5)^{2}, (39 - 13.5)^{2}$

Step 3 ： $Standard Deviation = \sqrt{\frac{(5 - 13.5)^{2} + (4 - 13.5)^{2} + (6 - 13.5)^{2} + (39 - 13.5)^{2}}{4}} \approx 14.6$