sample is greater than $2.6 \%$ ? Interpret this probability. Assume that $\sigma=1.35 \%$.

The probability is $\square$.
(Round to four decimal places as needed.)

Step 1 ：The question is asking for the probability that a sample is greater than 2.6%. This is a question about the normal distribution, because the standard deviation is given.

Step 2 ：The z-score formula is used to standardize the value to the standard normal distribution. The z-score is calculated as (X - μ) / σ, where X is the value, μ is the mean, and σ is the standard deviation. In this case, we don't know the mean, but we can assume it to be 0 because we are dealing with percentages and the standard deviation is given as 1.35%.

Step 3 ：The z-score for 2.6% is then calculated as \( \frac{2.6 - 0}{1.35} \), which gives a z-score of approximately 1.926.

Step 4 ：Once we have the z-score, we can find the probability that a value is greater than 2.6% by looking up the z-score in a standard normal distribution table. The probability is 1 - P(Z < z), where P(Z < z) is the cumulative probability up to the z-score.

Step 5 ：The probability that a sample is greater than 2.6% is approximately 0.0271 or 2.71%. This means that in a normal distribution with a standard deviation of 1.35%, about 2.71% of the values are expected to be greater than 2.6%.

Step 6 ：Final Answer: The probability is \( \boxed{0.0271} \).