The average acceleration is essentially the rate at which velocity changes. This is computed by taking away the beginning velocity from the concluding velocity and then dividing that by the time duration it took for this transformation to occur. The unit used to measure acceleration is meters per second squared (m/s^2). If the acceleration is positive, it signifies an increase in speed, whereas a negative value implies a decrease in speed.
| Topic | Problem | Solution |
|---|---|---|
| None | Question 23 1 pts You travel in circle of radius … | Given that the initial velocity is \(v = 5 \, m/s\) and the time interval is \(t = 2 \, s\). |
| None | Question 15 $1 \mathrm{pts}$ An airplane flies in… | Given that the airplane flies in a horizontal circle of radius 400 m at a uniform speed of 100 m/s. |
| None | 22) Two masses are attached by a weightless strin… | Given that the mass m1 = 78 kg, mass m2 = 42 kg, and the acceleration due to gravity g = 9.8 m/s^2. |
| None | Required information An object moving at constant… | Let the original speed be $v$ and the original radius be $r$. The original acceleration is $a = \fr… |
| None | A bike accelerates uniformly from rest to a speed… | 1. \(v^2 = u^2 + 2as \) |
| None | A car starts from rest and accelerates uniformly … | 1. Identify the knowns and unknowns: initial velocity \(v_0 = 0\mathrm{~m/s}\), time \(t = 11\mathr… |
| None | If the velocity of the object is given as \( V=12… | \(\mathrm{Step~1:}~\frac{dV}{dt} = A(t) = \frac{d(12t^{8} + 3t^2)}{dt}\) |
| None | A bike accelerates uniformly from rest to a speed… | Step 1: Rearrange the equation: \(v^{2} = u^{2} + 2as\) to solve for acceleration. Given that \(v =… |