The canonical form of a quadratic equation is illustrated as ax^2 + bx + c = 0. In this equation, 'a' represents the coefficient of x^2, 'b' is the coefficient of x, and 'c' stands for the constant. To discover the values of 'a', 'b', and 'c', it's essential to align the equation you have with this canonical form.
| Topic | Problem | Solution |
|---|---|---|
| None | Write the quadratic function in standard form. \[… | The quadratic function is already in standard form. The standard form of a quadratic function is \(… |
| None | 14. [4/5 Points] DETAILS PREVIOUS ANSWERS Write t… | The standard form of a quadratic function is \(h(x) = a(x-h)^2 + k\), where (h, k) is the vertex of… |
| None | Consider the following quadratic equation: \[ y^{… | Consider the following quadratic equation: \(y^{2}-6=3 y\) |
| None | Given the following function, (a) find the vertex… | The given function is a quadratic function in the form of \(f(x) = ax^2 + bx + c\), where \(a = 1\)… |
| None | Find $\mathrm{b}$ and $\mathrm{c}$ so that $y=14 … | The vertex form of a parabola is given by \(y=a(x-h)^{2}+k\) where \((h,k)\) is the vertex of the p… |
| None | Question 12 (1 point) Identify the following equa… | The given equation is \(y=x^{2}+5\). |
| None | Consider the function $f(x)=-3 x^{2}+30 x-6$ a. D… | We can complete the square, to get \(f(x) = 96 - 3(x - 5)^2\). |
| None | $y=-x^{2}+10 x+25$ | Given the equation: \(y=-x^{2}+10 x+25\) |
| None | $y=x^{2}+x-6$ | Given the equation: \(y=x^{2}+x-6\) |
| None | \( 5 x^{2}+3 x+1=0 \) | \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\) |