Find the fifth term and the nth term of the geometric sequence whose initial term $\mathrm{a}_{1}$ and common ratio $\mathrm{r}$ are given. \[ a_{1}=-9, r=-2 \] The fifth term of the geometric sequence is $\mathrm{a}_{5}=\square$. (Simplify your answer.)

Step 1 ：We are given the initial term \(a_{1} = -9\) and the common ratio \(r = -2\) of a geometric sequence.

Step 2 ：We are asked to find the fifth term of the sequence, denoted as \(a_{5}\).

Step 3 ：The nth term of a geometric sequence can be found using the formula: \(a_n = a_1 * r^{(n-1)}\), where \(a_n\) is the nth term, \(a_1\) is the first term, \(r\) is the common ratio, and \(n\) is the term number.

Step 4 ：Substitute \(a_1 = -9\), \(r = -2\), and \(n = 5\) into the formula to find \(a_{5}\).

Step 5 ：Calculate \(a_{5} = -9 * (-2)^{5-1} = -144\).

Step 6 ：Final Answer: The fifth term of the geometric sequence is \(\boxed{-144}\).