The polynomial $f(x)$ given below has -3 as a zero. \[ f(x)=x^{3}-7 x^{2}-x+87 \] Find the other zeros of $f(x)$. List the zeros separated by a comma.

Step 1 ：The given polynomial is \(f(x)=x^{3}-7 x^{2}-x+87\). It is known that -3 is a zero of the polynomial. This means that if we substitute -3 in place of x in the polynomial, the result will be zero.

Step 2 ：To find the other zeros of the polynomial, we can use the factor theorem which states that if a polynomial f(x) has a zero at x=a, then (x-a) is a factor of the polynomial.

Step 3 ：Since -3 is a zero of the polynomial, \((x - (-3)) = (x + 3)\) is a factor of the polynomial. We can divide the given polynomial by this factor to get a quadratic polynomial. The roots of this quadratic polynomial will be the other zeros of the original polynomial.

Step 4 ：The quadratic polynomial obtained after division is \(x^{2} - 10x + 29\).

Step 5 ：The roots of this quadratic polynomial are \(5 - 2i\) and \(5 + 2i\). These are complex numbers where i is the imaginary unit.

Step 6 ：Final Answer: The other zeros of the polynomial are \(\boxed{5 - 2i}\) and \(\boxed{5 + 2i}\).