Michelle borrows a total of $\$ 8000$ in student loans from two lenders. One charges $3.7 \%$ simple interest and the other charges $6.2 \%$ simple interest. She is not required to pay off the principal or interest for $3 \mathrm{yr}$. However, at the end of $3 \mathrm{yr}$, she will owe a total of $\$ 1113$ for the interest from both loans. How much did she borrow from each lender?

Step 1 ：Let's denote the amount borrowed from the lender who charges $3.7 \%$ simple interest as \(x\) and the amount borrowed from the lender who charges $6.2 \%$ simple interest as \(y\).

Step 2 ：From the problem, we know that the total amount borrowed is $8000, so we have the equation \(x + y = 8000\).

Step 3 ：Also, the total interest owed after 3 years is $1113. Since the interest is calculated using the formula \(Interest = Principal \times Rate \times Time\), we have the equation \(0.037x*3 + 0.062y*3 = 1113\).

Step 4 ：We can solve this system of equations using substitution or elimination method. Let's use the substitution method. We can express \(y\) as \(8000 - x\) from the first equation and substitute it into the second equation.

Step 5 ：Substituting \(y\) into the second equation, we get \(0.037x*3 + 0.062(8000 - x)*3 = 1113\).

Step 6 ：Solving this equation for \(x\), we get \(x = 5000\).

Step 7 ：Substituting \(x = 5000\) back into the first equation, we get \(5000 + y = 8000\), which gives \(y = 3000\).

Step 8 ：So, Michelle borrowed \(\boxed{\$5000}\) from the lender who charges $3.7 \%$ simple interest and \(\boxed{\$3000}\) from the lender who charges $6.2 \%$ simple interest.