Problem

Complete the table for the equation $3 x-5 y=15$, and graph the equation. \begin{tabular}{|c|c|} \hline $\mathbf{x}$ & $\mathbf{y}$ \\ \hline 0 & -3 \\ \hline 5 & 0 \\ \hline-5 & $\square$ \\ \hline \end{tabular}

Solution

Step 1 :The equation given is \(3x - 5y = 15\). We are asked to find the value of \(y\) when \(x = -5\). We can substitute \(x = -5\) into the equation and solve for \(y\).

Step 2 :Substitute \(x = -5\) into the equation, we get \(3(-5) - 5y = 15\).

Step 3 :Solving for \(y\), we get \(y = 6.0\).

Step 4 :\(\boxed{When \(x = -5\), \(y = 6\). So, the missing value in the table is \(6\). The completed table is:}

Step 5 :\begin{tabular}{|c|c|}\hline \(\mathbf{x}\) & \(\mathbf{y}\) \\ \hline 0 & -3 \\ \hline 5 & 0 \\ \hline-5 & 6 \\ \hline \end{tabular}

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Source: https://solvelyapp.com/problems/zVHgDCVdcP/

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