Solige the problem. The table shows the number of college students who prefer a given pizza topping. \begin{tabular}{r|crrr} toppings & freshman sophomore & junior & serior \\ \hline cheese & 10 & 16 & 22 & 23 \\ meat & 19 & 23 & 16 & 10 \\ veggie & 16 & 10 & 19 & 23 \end{tabular} Find the empirical probability that a randomly selected student prefers cheese toppings. 0.111 0.324 0.329 0.343

Step 1 ：The table shows the number of college students who prefer a given pizza topping. The table is as follows: \n \begin{tabular}{r|crrr} \n toppings & freshman sophomore & junior & serior \ \n \hline cheese & 10 & 16 & 22 & 23 \ \n meat & 19 & 23 & 16 & 10 \ \n veggie & 16 & 10 & 19 & 23 \n \end{tabular}

Step 2 ：To find the empirical probability that a randomly selected student prefers cheese toppings, we need to divide the total number of students who prefer cheese toppings by the total number of students.

Step 3 ：First, we need to calculate the total number of students who prefer cheese toppings. This can be done by adding the number of students from each class who prefer cheese toppings. The total number of students who prefer cheese toppings is \(10 + 16 + 22 + 23 = 71\).

Step 4 ：Next, we need to calculate the total number of students. This can be done by adding the number of students from each class who prefer each type of topping. The total number of students is \(10 + 16 + 22 + 23 + 19 + 23 + 16 + 10 + 16 + 10 + 19 + 23 = 207\).

Step 5 ：Finally, we divide the total number of students who prefer cheese toppings by the total number of students to get the empirical probability. The empirical probability is \(\frac{71}{207} \approx 0.343\).

Step 6 ：The empirical probability that a randomly selected student prefers cheese toppings is approximately 0.343. This is close to the third option provided in the question.

Step 7 ：Final Answer: The empirical probability that a randomly selected student prefers cheese toppings is \(\boxed{0.343}\).