Problem

(a) Complete this synthetic division table. 5) \begin{tabular}{rrrrr} -1 & 4 & 3 & 8 & 2 \\ & -5 & -5 & -10 & -10 \\ \hline-1 & -1 & -2 & -2 & -8 \end{tabular} (b) Write your answer in the following form: Quotient $+\frac{\text { Remainder }}{x-5}$. \[ \frac{-x^{4}+4 x^{3}+3 x^{2}+8 x+2}{x-5}=\llbracket+\frac{\square}{x-5} \]

Solution

Step 1 :Complete the synthetic division table as follows: \n 5) \begin{tabular}{rrrrr} -1 & 4 & 3 & 8 & 2 \ & -5 & -5 & -10 & -10 \ \hline -1 & -1 & -2 & -2 & -8 \end{tabular}

Step 2 :Write the answer in the form: Quotient $+\frac{\text{Remainder}}{x-5}$. So, we have: \n \[\frac{-x^{4}+4 x^{3}+3 x^{2}+8 x+2}{x-5}=-x^{3} - x^{2} - 2x - 2 + \frac{-8}{x-5}\]

Step 3 :Simplify the final answer using Python code. The final answer is: \n \[-x^{3} - x^{2} - 2x - 2 + \frac{-8}{x-5}\]

Step 4 :Box the final answer: \n \[\boxed{-x^{3} - x^{2} - 2x - 2 + \frac{-8}{x-5}}\]

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Source: https://solvelyapp.com/problems/zDPVCdEwqa/

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