EXAM 2 Review Question 19 of Find the equation of the line with the given slope and containing the given point. Slope $-\frac{1}{10} ;$ through $(-3,0)$ The equation of the line is $\square$. (Simplify your answer. Type your answer in slope-intercept form.)

Step 1 ：We are given the slope \(m = -\frac{1}{10}\) and a point on the line \((-3,0)\).

Step 2 ：We can substitute these values into the equation \(y = mx + b\) to solve for \(b\).

Step 3 ：Substituting the given values, we get \(0 = -\frac{1}{10}*(-3) + b\).

Step 4 ：Solving for \(b\), we find that \(b = -0.3\).

Step 5 ：Finally, we can write the equation of the line in slope-intercept form.

Step 6 ：\(\boxed{y = -\frac{1}{10}x - 0.3}\) is the equation of the line.