Problem

Solve the quadratic inequality \(x^2 - 4x + 3 > 0\).

Solution

Step 1 :Step 1: Rewrite the inequality as \((x-1)(x-3) > 0\) to find the roots of the equation.

Step 2 :Step 2: Determine the critical points from the roots, which are x = 1 and x = 3.

Step 3 :Step 3: Make a sign chart and test the intervals (-∞, 1), (1, 3), and (3, ∞) using the inequality \((x-1)(x-3) > 0\).

Step 4 :Step 4: From the sign chart, we find that \((x-1)(x-3) > 0\) on (-∞, 1) and (3, ∞).

From Solvely APP
Source: https://solvelyapp.com/problems/yu9xO1rAab/

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