Find the vertical asymptote. \[ \begin{array}{l} y=\frac{3 x-3}{x+1} \\ x=[?] \end{array} \]

Step 1 ：Given the function \(y=\frac{3x-3}{x+1}\), we are asked to find the vertical asymptote.

Step 2 ：The vertical asymptote of a rational function is found by setting the denominator equal to zero and solving for \(x\).

Step 3 ：So, we set \(x + 1 = 0\).

Step 4 ：Solving for \(x\), we find that \(x = -1\).

Step 5 ：Final Answer: The vertical asymptote is \(\boxed{x = -1}\).