Solve the following system of equations. \[ \left\{\begin{array}{l} y+x=-7 \\ 3 x^{2}-14 x-y=-5 \end{array}\right. \] If there is more than one solution, enter additional solutions with the "or" button If there is no real solution, use the "No solution" button. \[ (x, y)=\mathbb{( I D}, \mathbb{D} \] \[ \text { 믐 믐 } \sqrt{\square} \] Tor No solution

Step 1 ：The system of equations is a combination of a linear equation and a quadratic equation.

Step 2 ：To solve this system, substitute the expression for y from the first equation into the second equation. This will give a quadratic equation in terms of x.

Step 3 ：Solve the quadratic equation using the quadratic formula to find the solutions for x.

Step 4 ：Substitute the solutions for x back into the first equation to find the corresponding values of y.

Step 5 ：The solutions to the system of equations are \(\boxed{(1.33, -8.33)}\) and \(\boxed{(3, -10)}\).