Question 2 1 pt 1 Details A group of people were asked if they had run a red light in the last year. 404 responded "yes", and 202 responded "no". Find the probability that if a person is chosen at random, they have run a red light in the last year. Give your answer as a fraction or decimal Check Answer
Solution
Step 1 ：The question is asking for the probability that a person chosen at random has run a red light in the last year. To find this, we need to divide the number of people who responded 'yes' by the total number of people surveyed.
Step 2 ：Let's denote the number of 'yes' responses as \(y\), the number of 'no' responses as \(n\), and the total number of responses as \(t\).
Step 3 ：Given that \(y = 404\), \(n = 202\), we can calculate \(t\) as \(t = y + n = 404 + 202 = 606\).
Step 4 ：The probability \(p\) that a person chosen at random has run a red light in the last year is then given by \(p = \frac{y}{t} = \frac{404}{606} = 0.6666666666666666\).
Step 5 ：Final Answer: The probability that a person chosen at random has run a red light in the last year is approximately \(\boxed{0.67}\) or \(\boxed{\frac{2}{3}}\) in fraction form.
