Use a calculator to evaluate the expression. \[ \frac{2 \ln 10+\log 20}{\log 49-\ln 7} \] \[ \frac{2 \ln 10+\log 20}{\log 49-\ln 7} \approx \square \] (Do not round until the final answer. Then round to three decimal places as needed.)

Step 1 ：Calculate the natural logarithm of 10 and multiply it by 2, which gives \(2 \ln 10 = 4.605170185988092\)

Step 2 ：Calculate the logarithm base 10 of 20, which gives \(\log 20 = 1.3010299956639813\)

Step 3 ：Add the results from the first two steps, which gives \(4.605170185988092 + 1.3010299956639813 = 5.906200181652073\)

Step 4 ：Calculate the logarithm base 10 of 49, which gives \(\log 49 = 1.6901960800285136\)

Step 5 ：Calculate the natural logarithm of 7, which gives \(\ln 7 = 1.9459101490553132\)

Step 6 ：Subtract the result from the fifth step from the result from the fourth step, which gives \(1.6901960800285136 - 1.9459101490553132 = -0.2557140690267996\)

Step 7 ：Divide the result from the third step by the result from the sixth step, which gives \(\frac{5.906200181652073}{-0.2557140690267996} = -23.09689179062371\)

Step 8 ：Round the final result to three decimal places, which gives \(-23.09689179062371 \approx -23.097\)

Step 9 ：Final Answer: \(\boxed{-23.097}\)