As shown above, a classic deck of playing cards is made up of 52 cards, 26 of which are black and the other 26 are red. Each color is split into two suits of 13 cards each (clubs \& spades are black, and hearts \& diamonds are red). Each suit is split into 13 ranks of cards (Ace, 2-10, Jack, Queen, and King). If you select a card at random, what is the probability of getting... (a) ....a 10 of Clubs? (b) ...a Heart or Club? (c) ...a number smaller than 10 (counting the ace as a 1)? Give all your answers as reduced fractions. Add Work Check Answer

Step 1 ：We are given a standard deck of 52 playing cards, which consists of 26 black cards and 26 red cards. Each color is divided into two suits of 13 cards each (clubs and spades are black, hearts and diamonds are red). Each suit contains 13 ranks of cards (Ace, 2-10, Jack, Queen, and King).

Step 2 ：We are asked to find the probability of certain events when drawing a card from this deck.

Step 3 ：For part (a), we are asked to find the probability of drawing a 10 of Clubs. Since there is only one 10 of Clubs in the deck, the probability is \(\frac{1}{52}\).

Step 4 ：For part (b), we are asked to find the probability of drawing a Heart or a Club. There are 13 hearts and 13 clubs in the deck, so the probability is \(\frac{26}{52} = \frac{1}{2}\).

Step 5 ：For part (c), we are asked to find the probability of drawing a card with a number less than 10, counting the Ace as 1. There are 9 such cards (Ace through 9) in each of the 4 suits, so the probability is \(\frac{36}{52} = \frac{9}{13}\).

Step 6 ：Final Answer: \(\boxed{\frac{1}{52}}\) is the probability of drawing a 10 of Clubs, \(\boxed{\frac{1}{2}}\) is the probability of drawing a Heart or a Club, and \(\boxed{\frac{9}{13}}\) is the probability of drawing a card with a number less than 10.