Step 1 :Let vector \(\mathbf{s}=\langle-3,3\rangle\), and vector \(\mathbf{t}=\langle 3,-4\rangle\).
Step 2 :We are asked to perform the operation \(s+3t\).
Step 3 :First, we multiply vector \(\mathbf{t}\) by 3, which gives us \(\langle 9,-12 \rangle\).
Step 4 :Then, we add this resulting vector to vector \(\mathbf{s}\). The addition of two vectors is done component-wise.
Step 5 :So, the first component of the resulting vector is -3 + 9 = 6, and the second component is 3 + (-12) = -9.
Step 6 :Thus, the result of the operation \(s + 3t\) is the vector \(\langle 6, -9 \rangle\).
Step 7 :Final Answer: The result of the operation is the vector \(\boxed{\langle 6, -9 \rangle}\).