Use a Venn diagram to find the indicated probability. If $P(A \cup B)=0.63, P(A)=0.32$, and $P(A \cap B)=0.18$, find $P(B)$.

Step 1 ：Given that the probability of the union of two events A and B, denoted as \(P(A \cup B)\), is 0.63, the probability of event A, denoted as \(P(A)\), is 0.32, and the probability of the intersection of events A and B, denoted as \(P(A \cap B)\), is 0.18.

Step 2 ：The formula for the probability of the union of two events A and B is \(P(A \cup B) = P(A) + P(B) - P(A \cap B)\).

Step 3 ：We can rearrange this formula to solve for the probability of event B, \(P(B)\), which gives us \(P(B) = P(A \cup B) - P(A) + P(A \cap B)\).

Step 4 ：Substituting the given values into this formula, we get \(P(B) = 0.63 - 0.32 + 0.18\).

Step 5 ：Solving this equation gives us \(P(B) = 0.49\).

Step 6 ：Final Answer: The probability of event B, \(P(B)\), is \(\boxed{0.49}\).