Write the sum using sigma notation: $-3-9-27+\ldots-6561$ Question Help: Video Message instructor

Step 1 ：The given series is a geometric series where each term is multiplied by -3 to get the next term.

Step 2 ：The general form of a geometric series is \(a + ar + ar^2 + ar^3 + ... + ar^n\), where \(a\) is the first term and \(r\) is the common ratio.

Step 3 ：In this case, \(a = -3\) and \(r = -3\).

Step 4 ：We can write the sum using sigma notation as follows: \(\Sigma_{n=0}^{8} (-3)^n * -3\).

Step 5 ：This is because the first term is when \(n=0\), and the last term, -6561, is when \(n=8\) (since \(-3^8 = -6561\)).

Step 6 ：So, the sum using sigma notation is \(\Sigma_{n=0}^{8} (-3)^n * -3\).