Find $\frac{d y}{d x}$ using implicit differentiation. \[ 5 x^{3}=7 y^{2}-5 y \] \[ \frac{d y}{d x}=\square \]

Step 1 ：Given the equation \(5 x^{3}=7 y^{2}-5 y\), we are asked to find \(\frac{d y}{d x}\) using implicit differentiation.

Step 2 ：Differentiate both sides of the equation with respect to \(x\). This gives us the equation \(15x^2 = (14y - 5) \cdot \frac{dy}{dx}\).

Step 3 ：Solve the equation for \(\frac{dy}{dx}\). This gives us \(\frac{dy}{dx} = \frac{15x^2}{14y - 5}\).

Step 4 ：Final Answer: The derivative of \(y\) with respect to \(x\) is \(\boxed{\frac{15x^2}{14y - 5}}\).