Use the given information to find the P-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis). The test statistic in a two-tailed test is $z=1.95$.

Step 1 ：The test statistic in a two-tailed test is \(z=1.95\).

Step 2 ：The P-value is the probability that a random chance generated the data, if the null hypothesis is true. The smaller the P-value, the stronger the evidence against the null hypothesis.

Step 3 ：In a two-tailed test, the P-value is the probability that the absolute value of the test statistic is greater than the observed value, assuming the null hypothesis is true.

Step 4 ：To find the P-value, we need to find the area under the standard normal curve that is more extreme than our test statistic. Since it's a two-tailed test, we need to consider both tails of the distribution.

Step 5 ：After finding the P-value, we can compare it with the significance level (0.05 in this case). If the P-value is less than the significance level, we reject the null hypothesis. If the P-value is greater than the significance level, we fail to reject the null hypothesis.

Step 6 ：The calculated P-value is approximately 0.0512.

Step 7 ：The P-value is slightly greater than the significance level of 0.05.

Step 8 ：Final Answer: We \(\boxed{\text{fail to reject the null hypothesis}}\).