Enter the correct answer that completes the sentence below. Any line perpendicular to the graph of $6 x+7 y=6$ must have slope Any line perpendicular to the graph of $6 x+7 y=6$ must have slope $\square$. (Type an integer or a simplified fraction.)

Step 1 ：The slope of a line in the form of \(ax + by = c\) is \(-\frac{a}{b}\).

Step 2 ：So, the slope of the given line \(6x + 7y = 6\) is \(-\frac{6}{7}\).

Step 3 ：The slope of a line perpendicular to a given line is the negative reciprocal of the slope of the given line.

Step 4 ：So, the slope of the line perpendicular to the given line is \(-\frac{1}{-\frac{6}{7}}\).

Step 5 ：Final Answer: The slope of any line perpendicular to the graph of \(6 x+7 y=6\) is \(\boxed{\frac{7}{6}}\).