Differentiate the function. \[ \begin{array}{l} h(x)=e^{x^{6}+\ln (x)} \\ h^{\prime}(x)=\square \end{array} \]

Step 1 ：Given the function \(h(x)=e^{x^{6}+\ln (x)}\)

Step 2 ：Differentiate the function to find \(h'(x)\)

Step 3 ：By applying the chain rule, the derivative of the function is \(h'(x) = 6x^{5}e^{x^{6}+\ln (x)} + \frac{e^{x^{6}+\ln (x)}}{x}\)

Step 4 ：\(\boxed{h^{\prime}(x)=6x^{5}e^{x^{6}+\ln (x)} + \frac{e^{x^{6}+\ln (x)}}{x}}\) is the final answer