Problem

Use the functions $f(x)=-x^{2}+9$ and $g(x)=5 x+9$ to answer parts $(a)-(g)$. (a) Solve $f(x)=0$. (d) Solve $f(x)>0$. (g) Solve $f(x) \geq 9$. (b) Solve $g(x)=0$. (e) Solve $g(x) \leq 0$. (c) Solve $f(x)=g(x)$. (f) Solve $f(x)>g(x)$. (a) The solution to $f(x)=0$ is $x=-3,3$. (Type an integer or a fraction. Use a comma to separate answers as needed.) (b) The solution to $g(x)=0$ is $x=-\frac{9}{5}$. (Type an integer or a fraction. Use a comma to separate answers as needed.) (c) The solution of $f(x)=g(x)$ is $x=$ (Type an integer or a fraction. Use a comma to separate answers as needed.)

Solution

Step 1 :\(f(x) = -x^{2} + 9 = 0\)

Step 2 :\(x^{2} = 9\)

Step 3 :\(x = \pm3\)

Step 4 :\(\boxed{x = -3, 3}\)

Step 5 :\(g(x) = 5x + 9 = 0\)

Step 6 :\(x = -\frac{9}{5}\)

Step 7 :\(\boxed{x = -\frac{9}{5}}\)

Step 8 :\(f(x) = g(x)\)

Step 9 :\(-x^{2} + 9 = 5x + 9\)

Step 10 :\(x^{2} + 5x = 0\)

Step 11 :\(x(x + 5) = 0\)

Step 12 :\(\boxed{x = 0, -5}\)

Step 13 :\(f(x) > 0\)

Step 14 :\(-x^{2} + 9 > 0\)

Step 15 :\(x^{2} < 9\)

Step 16 :\(\boxed{-3 < x < 3}\)

Step 17 :\(g(x) \leq 0\)

Step 18 :\(5x + 9 \leq 0\)

Step 19 :\(x \leq -\frac{9}{5}\)

Step 20 :\(\boxed{x \leq -\frac{9}{5}}\)

Step 21 :\(f(x) > g(x)\)

Step 22 :\(-x^{2} + 9 > 5x + 9\)

Step 23 :\(x^{2} + 5x < 0\)

Step 24 :\(\boxed{-5 < x < 0}\)

Step 25 :\(f(x) \geq 9\)

Step 26 :\(-x^{2} + 9 \geq 9\)

Step 27 :\(x^{2} \leq 0\)

Step 28 :\(\boxed{x = 0}\)

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Source: https://solvelyapp.com/problems/vIADvVoyKB/

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