Step 1 :The given trinomial is \(2x^{2} + 14x + 24\).
Step 2 :We need to find two numbers that add up to 14 and multiply to 48. The numbers that satisfy these conditions are 6 and 8.
Step 3 :We can write the middle term (14x) as the sum of 6x and 8x. So, the trinomial becomes \(2x^{2} + 6x + 8x + 24\).
Step 4 :Next, we factor by grouping. The first two terms can be grouped together, and the last two terms can be grouped together. This gives us \(2x(x + 3) + 8(x + 3)\).
Step 5 :We can see that \((x + 3)\) is a common factor. Factoring out \((x + 3)\) gives us \((x + 3)(2x + 8)\).
Step 6 :We can further factor out a 2 from the second term to get \(2(x + 3)(x + 4)\).
Step 7 :So, the completely factored form of the given trinomial \(2x^{2} + 14x + 24\) is \(\boxed{2(x + 3)(x + 4)}\).