How many times greater is the intensity of sound from a concert speaker at a distance of 14 meters than the intensity at a distance of 70 meters? The intensity of sound is $\square$ times as strong at $14 \mathrm{~m}$ as at $70 \mathrm{~m}$. (Simplify your answer.)

Step 1 ：The intensity of sound follows the inverse square law, which states that the intensity is inversely proportional to the square of the distance from the source.

Step 2 ：Therefore, if the distance is increased by a factor of k, the intensity decreases by a factor of k^2.

Step 3 ：In this case, the distance is increased by a factor of 70/14 = 5, so the intensity should decrease by a factor of 5^2 = 25.

Step 4 ：Therefore, the intensity of sound at 14 meters is 25 times greater than the intensity at 70 meters.

Step 5 ：Final Answer: The intensity of sound is \(\boxed{25}\) times as strong at 14 meters as at 70 meters.