Solve the triangle. \[ a=3, b=9, c=8 \]

Step 1 ：\(\cos(C) = \frac{a^2 + b^2 - c^2}{2ab}\)

Step 2 ：Substitute the given values into the equation: \(\cos(C) = \frac{3^2 + 9^2 - 8^2}{2*3*9} = \frac{10}{27}\)

Step 3 ：Calculate the angle C: \(C = \cos^{-1}(\frac{10}{27})\)

Step 4 ：Use the Law of Sines to find another angle: \(\sin(A) = \frac{a*\sin(C)}{c}\)

Step 5 ：Substitute the given values into the equation: \(\sin(A) = \frac{3*\sin(\cos^{-1}(\frac{10}{27}))}{8}\)

Step 6 ：Calculate the angle A: \(A = \sin^{-1}(\frac{3*\sin(\cos^{-1}(\frac{10}{27}))}{8})\)

Step 7 ：Find the third angle by subtracting the other two angles from 180 degrees: \(B = 180 - A - C\)

Step 8 ：So, the solution to the triangle is \(A = \sin^{-1}(\frac{3*\sin(\cos^{-1}(\frac{10}{27}))}{8})\), \(B = 180 - A - C\), and \(C = \cos^{-1}(\frac{10}{27})\)

Step 9 ：\(\boxed{A = \sin^{-1}(\frac{3*\sin(\cos^{-1}(\frac{10}{27}))}{8}), B = 180 - A - C, C = \cos^{-1}(\frac{10}{27})}\)