Find $m$ so that $x+5$ is a factor of $-2 x^{4}-2 x^{3}+47 x^{2}+31 x+m$.

Step 1 ：The problem is to find the value of $m$ such that $x+5$ is a factor of the polynomial $-2 x^{4}-2 x^{3}+47 x^{2}+31 x+m$.

Step 2 ：We can use the factor theorem to solve this problem. The factor theorem states that a polynomial $f(x)$ has a factor $(x - h)$ if and only if $f(h) = 0$. In this case, we have the factor $x + 5$, so we can set $x = -5$ and solve for $m$.

Step 3 ：Substituting $x = -5$ into the polynomial gives us $m - 2(-5)^4 - 2(-5)^3 + 47(-5)^2 + 31(-5) = 0$.

Step 4 ：Solving this equation gives us $m = -20$.

Step 5 ：Therefore, the value of $m$ that makes $x+5$ a factor of $-2 x^{4}-2 x^{3}+47 x^{2}+31 x+m$ is \(\boxed{-20}\).