Simplify the expression \(2\sqrt{8} + 3\sqrt{27}\).

Step 1 ：First, we simplify each term under the radical separately. We can express 8 as \(2^3\) and 27 as \(3^3\), so we have \(2\sqrt{2^3} + 3\sqrt{3^3}\).

Step 2 ：The square root of a cube is the original number times the square root of the number, so we can simplify to \(2*2\sqrt{2} + 3*3\sqrt{3}\).

Step 3 ：Multiplying the coefficients gives us \(4\sqrt{2} + 9\sqrt{3}\).