In your sock drawer you have 6 blue, 8 gray, and 3 black socks. Half asleep one morning, you grab one sock and then you grab another sock at random and put them on. Find the probability that you end up wearing 2 blue socks. $67 \%$ $32 \%$ $11 \%$ $35 \%$

Step 1 ：In your sock drawer you have 6 blue, 8 gray, and 3 black socks. Half asleep one morning, you grab one sock and then you grab another sock at random and put them on. We need to find the probability that you end up wearing 2 blue socks.

Step 2 ：First, calculate the total number of socks. There are 6 blue, 8 gray, and 3 black socks, so the total number of socks is \(6 + 8 + 3 = 17\).

Step 3 ：Next, calculate the probability of picking a blue sock first. This is the number of blue socks divided by the total number of socks, which is \(6 / 17 \approx 0.35294117647058826\).

Step 4 ：Then, calculate the probability of picking a blue sock second. This is the number of remaining blue socks divided by the total number of remaining socks, which is \(5 / 16 = 0.3125\).

Step 5 ：Finally, calculate the probability of both events happening. This is the product of the two probabilities calculated above, which is \(0.35294117647058826 * 0.3125 = 0.11029411764705883\).

Step 6 ：So, the probability that you end up wearing 2 blue socks is approximately \(\boxed{11 \%}\).