Solve for $n$. \[ K=\frac{a}{b(c+n)} \] \[ n= \]

Step 1 ：Multiply both sides of the equation by \(b(c+n)\) to get rid of the denominator on the right side, resulting in \(Kb(c+n) = a\).

Step 2 ：Distribute \(bK\) to \(c\) and \(n\), resulting in \(Kbc + Kbn = a\).

Step 3 ：Subtract \(bcK\) from both sides to isolate \(n\), resulting in \(n = -c + \frac{a}{Kb}\).

Step 4 ：Final Answer: \(n = \boxed{-c + \frac{a}{Kb}}\)