Write a single iterated integral of a continuous function $f$ over the following region. The region bounded by the triangle with vertices $(0,0),(24,0)$, and $(12,12)$.

Step 1 ：Determine the limits of integration for the $x$ and $y$ variables over the triangular region

Step 2 ：Split the region into two parts: the first part bounded by $y=0$, $y=x$, and $x=12$, and the second part bounded by $y=0$, $y=24-x$, and $x=12$

Step 3 ：For the first part, set the limits of integration for $y$ from $0$ to $x$, and for $x$ from $0$ to $12$

Step 4 ：For the second part, set the limits of integration for $y$ from $0$ to $24-x$, and for $x$ from $12$ to $24$

Step 5 ：Write the single iterated integral for the entire region as the sum of the integrals for the two parts: \(\int_{0}^{12} \int_{0}^{x} f(x,y) \, dy \, dx + \int_{12}^{24} \int_{0}^{24-x} f(x,y) \, dy \, dx\)

Step 6 ：\(\boxed{\int_{0}^{12} \int_{0}^{x} f(x,y) \, dy \, dx + \int_{12}^{24} \int_{0}^{24-x} f(x,y) \, dy \, dx}\)