Find the equation of the line parallel to the line \(4x - 2y = 6\) and passing through the point \((1,2)\)

Step 1 ：Step1: Convert the equation of the line into slope-intercept form (\(y = mx + b\)), where \(m\) is the slope. The slope of a parallel line would be the same. So, rearrange \(4x - 2y = 6\) to slope-intercept form to find the slope.

Step 2 ：Step2: \(4x - 2y = 6\) can be written as \(2y = 4x - 6\), and then \(y = 2x - 3\). So, the slope \(m\) of the line is 2.

Step 3 ：Step3: Use the point-slope form of a line, which is \(y - y1 = m(x - x1)\), where \((x1, y1)\) is a given point on the line (in this case, \((1,2)\)) and \(m\) is the slope of the line. Substituting the given point and the slope into the equation gives us the equation of the line.

Step 4 ：Step4: Substituting \(m = 2\), \(x1 = 1\), and \(y1 = 2\) into \(y - y1 = m(x - x1)\) gives \(y - 2 = 2(x - 1)\).

Step 5 ：Step5: Simplify the equation to slope-intercept form to get the equation of the line.