59 Determine the interval(s) on which the function $h(x)=2 e^{2 x}-4 x$ is increasing. Use interval notation, and enter $\infty$ as "INF" and $-\infty$ as "-INF", and the union symbol as " $U$ " if necessary. Do not include any spaces in your answer.

Step 1 ：Find the derivative of \(h(x)=2e^{2x}-4x\), which is \(h'(x)=4e^{2x}-4\).

Step 2 ：Set the derivative greater than zero and solve for \(x\), which gives us \(4e^{2x}-4>0\).

Step 3 ：Simplify the inequality to \(e^{2x}>1\).

Step 4 ：Take the natural logarithm on both sides to get \(2x>\ln(1)\).

Step 5 ：Since \(\ln(1)=0\), we have \(2x>0\), so \(x>0\).

Step 6 ：\(\boxed{x>0}\) is the interval where the function \(h(x)=2e^{2x}-4x\) is increasing.