Given the equation of a hyperbola as \(4x^2 - 9y^2 = 36\), find the vertex form of this hyperbola.

Step 1 ：Step 1: Rearrange the equation so that it equals 1: \(\frac{x^2}{9} - \frac{y^2}{4} = 1\)

Step 2 ：Step 2: Recognize the standard form of the equation of a hyperbola: \(\frac{(x-h)^2}{a^2} - \frac{(y-k)^2}{b^2}=1\).

Step 3 ：Step 3: By comparison, we can see that h=0, k=0, a=3, and b=2.

Step 4 ：Step 4: Substitute these values into the standard form equation.