Problem
A normal distribution has a mean of 98 and a standard deviation of 4 . Find the $z$-score for a data value of 90. Round to two decimal places Question Help: $\square$ Video Submit Question
Solution
Step 1 ：Given that the mean (\(\mu\)) is 98, the standard deviation (\(\sigma\)) is 4, and the data value (\(X\)) is 90.
Step 2 ：The formula to calculate the z-score is \(Z = \frac{X - \mu}{\sigma}\).
Step 3 ：Substitute the given values into the formula: \(Z = \frac{90 - 98}{4} = -2.0\).
Step 4 ：So, the z-score for a data value of 90 is \(\boxed{-2.00}\).
