Step 1 :Calculate the sample proportion (p̂) as the number of successful challenges divided by the total number of challenges. In this case, p̂ = \(\frac{36}{132}\) = 0.2727 or 27.27%.
Step 2 :Calculate the standard error (SE) as \(\sqrt{ p̂(1 - p̂) / n }\), where n is the total number of challenges. In this case, SE = \(\sqrt{ 0.2727(1 - 0.2727) / 132 }\) = 0.0385.
Step 3 :Calculate the 95% confidence interval as p̂ ± 1.96*SE. In this case, the confidence interval is 0.2727 ± 1.96*0.0385 = (0.197, 0.349) or (19.7%, 34.9%).
Step 4 :Compare the 95% confidence intervals for the percentage of successful challenges made by the women (19.7% to 34.9%) and the men (24.2% to 38.6%). The two intervals overlap, which means that we cannot conclude that one gender is more successful than the other based on these confidence intervals.
Step 5 :Therefore, the correct answer is E. Since the two confidence intervals overlap, neither gender appears to be substantially more successful in their challenges. \(\boxed{\text{Answer: E}}\)